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Law of Constant Proportions

Calculate the

Question

Calculate the %composition of:-
Iron in ferric oxide, Fe₂O₃ ( Atomic mass of Fe = 56)
Nitrogen in Urea, H₂NCONH₂Ask

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Solution

Molecular mass of Fe₂O₃ = 56x2 + 16x3 = 160
Mass of Iron = 112
% of Fe =
= 70%

Molecular mass of Urea = 60
Mass of Nitrogen = 28
% of nitrogen = (28x 100) / 60
= 46.66 %

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