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Question

Q.1= A piece of equipment cost a certain factory Rs 600,000.If it depreciates in value ,15% the first year ,13.5% the next year ,12% the third year ,and so on .What will be its value at the end of 10 years ,all percentages applying to the original cost ?

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Solution

Dear Student!

Here is the answer to your query.

Cost of equipment in the end of first year= Rs 600000 – 15% of 600000

= Rs 600000 – Rs 90000 = Rs 510000

Cost of equipment in the end of second year = Rs 600000 – 13.5% of 600000

= Rs 600000 – Rs 81000 = Rs 519000

Cost of equipment in the end of third year = Rs 600000 – 12% of Rs 600000

= Rs 600000 – Rs 72000 = Rs 528000

The numbers 510000, 519000, 528000 are in A.P.

Whose first term in 510000 and common difference is 9000

∴ Cost of equipment at the end of 10 years

= a + (10 – 1) d = 510000 + 81000 = Rs 591000

Cheers!


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