a bus starts from rest and attains 40 km/h velocity after 10 seconds .calculate the acceleration of the bus in (i) km/h²(ii)m/s²

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Solution

Time = 10 sec = 10/(60 X60) = 1/360 sec
Acceleration = change in velocity/ time = (40 - 0)/(1/360) = 1440 km/h2
Change in the Velocity = 40 km/h = 100/9 m/s
Acceleration = 100/(9 x 10) = 10/9 m/s2

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