Question

.An electric kettle rated 1000W, 220V is used to bring water at 20 degrees to its boiling point. If the kettle is switched on for 10 minutes. Calculate:

1. The resistance of the element of kettle

2. Current flowing through the element

Mass of water in the kettle.

Answer 1

Power = V²/R
220²/R = 1000
R = 48.4 ohm

I²R = Power = I²*48.4 = 1000
4.54 A = I

I²Rt = mC(T₂-T₁)
4.54²*48.4*10*60 = m*4.186*80
1787 gms = m
So, the weight of water being heated is 1.7 kgs