Question

The measure of an angle is 6more than the twice of its complementary angle. Find the measures of both the angles

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{required}\mathrm{angle}=x° \\ \mathrm{then},\mathrm{measure}\mathrm{of}\mathrm{its}\mathrm{complement}=\left(90-x\right)° \\ \mathrm{Now},\mathrm{according}\mathrm{to}\mathrm{question}, \\ x=2\left(90-x\right)+6 \\ \Rightarrow x=180-2x+6 \\ \Rightarrow x+2x=186 \\ \Rightarrow 3x=186 \\ \Rightarrow x=\frac{186}{3} \\ \Rightarrow x=62 \\ \therefore \mathrm{required}\mathrm{angle}=62° \\ \mathrm{measure}\mathrm{of}\mathrm{its}\mathrm{complement}=90°-62°=28° \end{gathered}$$