Question

Subtract the sum of -36/11 and 49/22 from the sum of 33/8 and -19/4.

Answer 1

$$\begin{gathered} \left[\frac{33}{8}+\left(-\frac{19}{4}\right)\right]-\left[\left(-\frac{36}{11}\right)+\frac{49}{22}\right] \\ =\left[\frac{33-38}{8}\right]-\left[\frac{-72+49}{22}\right] \\ =\left(-\frac{5}{8}\right)-\left(-\frac{23}{22}\right) \\ =\frac{-55-\left(-92\right)}{88} \\ =\frac{-55+92}{88} \\ =\frac{37}{88} \end{gathered}$$