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Question
The amplitude of themagnetic field part of a harmonic electromagnetic wave in vacuum isB0 = 510 nT. What is the amplitude of the electricfield part of the wave?
The amplitude of themagnetic field part of a harmonic electromagnetic wave in vacuum isB0 = 510 nT. What is the amplitude of the electricfield part of the wave?
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Solution
Amplitudeof magnetic field of an electromagnetic wave in a vacuum,
B0= 510 nT = 510 × 10−9T
Speed of light in avacuum, c = 3 × 108 m/s
Amplitude of electricfield of the electromagnetic wave is given by the relation,
E = cB0
=3 × 108 × 510 × 10−9 =153 N/C
Therefore, the electricfield part of the wave is 153 N/C.
Amplitudeof magnetic field of an electromagnetic wave in a vacuum,
B0= 510 nT = 510 × 10−9T
Speed of light in avacuum, c = 3 × 108 m/s
Amplitude of electricfield of the electromagnetic wave is given by the relation,
E = cB0
=3 × 108 × 510 × 10−9 =153 N/C
Therefore, the electricfield part of the wave is 153 N/C.
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