The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is theamplitude of the electric field part of the wave?

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Solution

It is given that the amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B 0 =510nT.

The formula of the amplitude of electric field of the electromagnetic wave is,

E=c B 0

Substitute the values in above expression.

E=3× 10 8 ×510× 10 −9 =153 N/C

Thus, the amplitude of the electric field part of the wave is 153 N/C.

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