Question

the length of a rectangle exceeds the breath by 8 cm. find the area of the rectangle, if its perimeter is 180 cm.

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{length}\mathrm{be}\mathrm{x}+8\mathrm{and}\mathrm{breadth}\mathrm{is}\mathrm{x}\mathrm{unit}\mathrm{so}, \\ 2\left(\mathrm{x}+8\right)+2\mathrm{x}=180 \\ 4\mathrm{x}+16=180 \\ \mathrm{x}=\frac{180-16}{4}=41 \\ \mathrm{So}\mathrm{area}=\mathrm{length}\times \mathrm{breadth} \\ =\left(41+8\right)\times 8 \\ =49\times 8 \\ =392\mathrm{square}\mathrm{unit} \end{gathered}$$