The melting point of three solids X , Y and Z are
298 Degree Kelvin , 314 Degree Kelvin , 398 degree Kelvin.

Arrange these in increasing order of their interparticle force of attraction

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Solution

Higher the interparticle force of attraction, higher will be the melting point, as more heat energy will be required to overcome the forces of attraction between the particles.
Hence, the answer would be
298 K, 314K, 398 K

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The melting point of three solids X , Y and Z are 298 Degree Kelvin , 314 Degree Kelvin , 398 degree Kelvin. Arrange these in increasing order of their interparticle force of attraction

Higher the interparticle force of attraction, higher will be the melting point, as more heat energy will be required to overcome the forces of attraction between the particles. Hence, the answer would be 298 K, 314K, 398 K

The melting point of three solids X , Y and Z are
298 Degree Kelvin , 314 Degree Kelvin , 398 degree Kelvin.

Arrange these in increasing order of their interparticle force of attraction

Higher the interparticle force of attraction, higher will be the melting point, as more heat energy will be required to overcome the forces of attraction between the particles.
Hence, the answer would be
298 K, 314K, 398 K