MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Melting Point

The melting p...

Question

The melting points of three solids X, Y and Z are 298 K, 314 K and 398 K respectively. Arrange these in increasing order of their inter particle force of attraction.

Open in App

Solution

Higher the melting point, higher the inter-particle force of attraction.
Increasing order of their inter-particle force of attraction:
X (298 K) < Y (314 K) < Z (398 K)

Suggest Corrections

thumbs-up

16

Similar questions

Q. The melting points of three solids X, Y and Z are 298K, 310K and 400K, respectively. Arrange these in increasing order of their inter-particle force of attraction.

Q. 1)give reason:temperature of a liquid does not change when it boils.
2)The melting points of 3 solids X, Y ,Z are 314K,268K and 346K respectively. Arrange these in increasing order of their inter particle force of attraction .What is the basis of arrangement ?

Q. Melting points of three solids A, B and C are 298K, 310K and 400K respectively. Arrange these in increasing order of force of attraction.

Q. The melting points of four solids A, B, C and D are

78^{o} C, 213^{o} C, 100^{o} C

154^{o} C .

Arrange them in increasing order of their interparticle forces of attraction.

Q. A few substances are arranged in order of increasing force of attraction between their particles. Which one of the following represents a correct arrangement?

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Can Matter Change Its State?

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard IX Chemistry

Join BYJU'S Learning Program

CrossIcon