Question

The ratio of distances traversed in successive intervals of time when a body falls freely under gravity from a certain height is?

Answer 1

Distance travelled in time t under free fall is :
s = 1/2gt²

Distance travel in 1st second = 1/2g

Distance travel in 2nd second = distance travelled in 2 seconds - distance travelled in 1 second
1/2g2² - 1/2g = 3/2 g

Ration of these distance = $\frac{{\displaystyle \frac{3g}{2}}}{{\displaystyle \frac{1}{2}}g}$
Ratio = 3:2