The sum of 1st n_____ natural numbers is equal to n square.
The square of a multiple of 10 always ends in _ number of zeros.
A number cannot have a___ square.
Cube root of a negative is_.
Cubes of even numbers are _ while cubes of odd numbers are .
The sum of the cubes of first n natural numbers is equal to the _ of their sum.

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Solution

Answer :

The sum of 1st n ODD natural numbers is equal to n square.

The square of a multiple of 10 always ends in TWO number of zeros.

A number cannot have a NEGATIVE square.

Cube root of a negative is NEGATIVE .

Cubes of even numbers are EVEN while cubes of odd numbers are ODD .

The sum of the cubes of first n natural numbers is equal to the ${[\frac{n (n + 1)}{2}]}^{2}$ of their sum.

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