Theelectrical resistance in ohms of a certain thermometer varies withtemperature according to the approximate law:
R = Ro[1 + α (T –To)]
Theresistance is 101.6 Ω at the triple-point of water 273.16 K,and 165.5 Ω at the normal melting point of lead (600.5 K). Whatis the temperature when the resistance is 123.4 Ω?
Itis given that:
R= R0[1 + α (T –T0)] …(i)
Where,
R0and T0 are the initial resistance and temperaturerespectively
R and Tare the final resistance and temperature respectively
αis a constant
At the triple point ofwater, T0 = 273.15 K
Resistance of lead, R0= 101.6 Ω
At normal melting pointof lead, T = 600.5 K
Resistance of lead, R= 165.5 Ω
Substituting thesevalues in equation (i), we get:
For resistance, R1= 123.4 Ω