Question

TWO DICE ARE THROWN SIMULTANEOUSLY. FIND PROBABILITY OF GETTING A MULTIPLE OF 3 AS THE SUM

A) 1/2

B) 1/3

C) 1/4

D) 5/6

Answer 1

When two dice are thrown then total no. of possible outcomes = 36
Now , the outcomes in which we get a multiple of 3 as the sum are :
{(1,2); (1,5) ; (2,1) ; (2,4) ; (3,3) ; (3,6) ;(4,2); (4,5) ; (5,1) ; (5,4); (6,3); (6,6)}
no. of favorable outcomes = 12
$\mathrm{required}\mathrm{probability}=\frac{\mathrm{no}.\mathrm{of}\mathrm{favorable}\mathrm{outcomes}}{\mathrm{total}\mathrm{possible}\mathrm{outcomes}}=\frac{12}{36}=\frac{1}{3}$