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Question

two identical resistors each of resistance 3 ohm are connected in turn 1) series 2) parallel to a battery of 120 V . calculate the ratio of power consumed in the two cases

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Solution

Given,
R1=3 ohmR2=3 ohm
V=120 V
Series combination:
Resultant resistance is given by,
Rs=R1+R2=3+3=6 ohmPower, Ps=V2Rs=12026=2400 WParallel combination,Resultant resistance is given byRP=R1R2R1+R2=3×33+3=96=1.5 ohmPower,PP=V2RP=12021.5=9600 WNow, Ps:PP=2400 :9600=1:4

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