Question

Two resistors of 10 ohm and 20 ohm are connected in series to a 20 V battery. Calculate the potential difference across the 10 ohm resistor.

Answer 1

The details of the circuit are as follows:

Resistance, R1	10 Ω
Resistance, R2	20 Ω
Voltage	20 V

Since the resistors are in series so the equivalent resistance, R = R₁ + R₂ = 10 + 20 = 30 Ω
Therefore, we can find the current in the circuit by using Ohm's law:
V = I R
I = V/R = 20/30 = 2/3 A
Therefore, the potential difference across the R₁ resistor,
$V_1=I{R}_1=\frac{2}{3}\times 10=\frac{20}{3}\text{V}$