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Question

PV diagram of an ideal gas is shown in the figure. Work done by the gas in process ABCD is


A
4P0V0
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B
2P0V0
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C
3P0V0
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D
P0V0
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Solution

The correct option is C 3P0V0
From the given PV diagram, it can be observed that,
AB is an Isobaric process; BC is an Isochoric process; CD is an Isobaric process.
Work done during process AB, (WAB)=P×ΔV=P0V0
Similarly,
Work done during process BC, (WBC)=0
Work done during process CD, (WCD)=4P0V0
Total work done in process ABCD is
WABCD=WAB+WBC+WCD=P0V0+0+4P0V0=3P0V0
Hence, option (c) is the correct answer.

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