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Question

P-V plots for two gases during an adiabatic process are given in the figure.
Plot A and Plot B can correspond to: (assume ideal behaviour)

A
He andO2
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B
SO2 and Ar
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C
O2 and He
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D
Ar and O2
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Solution

The correct option is C O2 and He
PVγ = constant (in ~adiabatic)
differentiating,
dp.Vγ+γPVγ1dV=0
dpdV=γPV
Hence, from same starting point, slope is greates for gas with higher value of γ. Now, γ=1+2f where f : degress of freedom. Higher the vlaue of f, lower is γ So, 'A' has higher 'f'' compared to 'B' (SO2,Ar) and (O2,He) both are possible

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