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Question

PV plots for two gases during an adiabatic processes are shown in the figure. Plots 1 and 2 should correspond respectively to


A
He and O2
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B
O2 and He
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C
He and Ar
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D
O2 and N2
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Solution

The correct option is B O2 and He
For an adiabatic process,
PVγ=constant
For monatomic gas, γ=CPCV=1.67
For diatomic gas, γ=1.4
γdiatomic<γmonatomic
Since slope of adiabatic curve, dPdV=γPV
Thus slope of monoatomic will be more than diatomic gas,
Hence, curve 1 represents graph for diatomic gas and curve 2 represents graph for a monomatomic gas
Correct option is (b)

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