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Latent Heat of Fusion

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Question

what do you mean when you say that the latent heat of fusion of ice is3.34*10^{5 j/kg.}

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Solution

This means that 3.34*10⁵ J of heat energy would be required to convert 1 kg of ice into 1 kg of water at it's melting point.

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1 kg of ice at $0^{\circ} C$ is mixed with 1 kg of steam at $100^{\circ} C$ . What will be the composition of the system when thermal equilibrium is reached? Latent heat of fusion of ice = $3.36 \times 10^{5} J k g^{- 1}$ and latent heat of vaporization of water = $2.26 \times 10^{6} J k g^{- 1}$

Q. Calculate the amount of heat reqiured to convert

1 kg

- 10^{\circ} C

100^{\circ} C

. Specific heat capacity of ice is

= 2100 J {k g}^{- 1} K^{- 1}

, latent heat of fusion of ice

= 3.36 \times 10^{5} J {k g}^{- 1}

, specific heat capacity of water

= 4200 J {k g}^{- 1} K^{- 1}

and latent heat of vapourization of water

= 2.25 \times 10^{6} J {k g}^{- 1}

.

Q. What is the amount of heat energy required to convert ice of mass 20 Kg at

- 4^{0} C

20^{0} C

? Use the relevant option for calculation.
a) Latent heat of fusion of ice 3.34 x

10^{5}

J / Kg.
b) Specific heat capacity of water is 4180 J / Kg / K
c) Specific heat of ice 2093 J / Kg / K

Q. Assertion :Latent heat of fusion of ice is

336000

k g^{- 1}

. Reason: Latent heat refers to change of state without any change in temperature.

What do you understand by latent heat of fusion and how it is related to melting point?

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