Question

What happens when bromine attacks CH2 = CH CH2 C≡Η

Answer 1

As alkene is more reactive than alkyne due to longer bond length bromination will occur at double bond (C1) first

Thus the product formed will be as follows,

CH₂ = CH CH₂-C≡CΗ + Br₂ ---------> BrCH₂-CH(Br)-CH₂-C≡CΗ

(Note: If bromine is in excess, then only it will attack the triple bond and give addition product but it will be very unstable hence not shown)