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Question

what happens when

a) dilute sulphuric acid is poured on a copper plate?

b) iron nails are placed in blue copper sulphate solution?

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Solution

a). Copper displaces the hydrogen from its sulphate and forms copper sulphate as:

Cu +H2SO4 --> CuSO4 + H2

b). When iron nails are dipped in blue copper sulphate solution, the iron displaces copper an solution color changes to light green of ferrous sulphate as:

Fe + CuSO4 --> FeSO4 + Cu


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