what happens when
a) dilute sulphuric acid is poured on a copper plate?
b) iron nails are placed in blue copper sulphate solution?
a). Copper displaces the hydrogen from its sulphate and forms copper sulphate as:
Cu +H2SO4 --> CuSO4 + H2
b). When iron nails are dipped in blue copper sulphate solution, the iron displaces copper an solution color changes to light green of ferrous sulphate as:
Fe + CuSO4 --> FeSO4 + Cu