Question

what volume of 75% sulfuric acid by mass is required to prepare 1.5 Lt of 0.2 M sulfuric acid solution ??

Answer 1

Moles of H₂SO₄ = c $\times$ V
where, c is concentration in molarity = 0.2 M
V is volume in litres= 1.5 L
Substituting the values, moles = 0.2 $\times$ 1.5 = 0.3 moles
Mass of sulphuric acid = moles $\times$ molar mass = 0.3 $\times$ 98 = 29.4 g
Concentration of H₂SO₄ solution =75%
75 g of H₂SO₄ is present in 100 ml
29.4 g of H₂SO₄ is present in = $\frac{100\times 29.4}{75}=39.2\text{ml}$
39.2 ml of 75% solution is required to prepare 1.5 L of 0.2 M H₂SO₄ solution.