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Question

Write the molecular orbital configuration of N2 and N2+ . Also calculate their bond order?

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Solution

Orbital configuration of N2
σ1s2, σ*1s2, σ2s2, σ*2s2, π2py2 π2pz2, σ2px2

Orbital configuration of N2+
σ1s2, σ*1s2, σ2s2, σ*2s2, π2py2 π2pz2, σ2px1

Bond order = (no. of electrons in bonding orbitals - no. of electrons in antibonding orbitals)2

Bond order of N2 = (10-4)2 = 3

Bond order of N2+ = (9-4)2= 2.5

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