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Question
p(x) = 4x4−2x3−6x2+x−5 becomes divisible by q(x) = 2x2+x−1 if we
p(x) = 4x4−2x3−6x2+x−5 becomes divisible by q(x) = 2x2+x−1 if we
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Solution
The correct option is A add (6)
Lets divide p(x)=4x4−2x3−6x2+x−5 by q(x)=2x2+x–1 as shown below:
Hence −6 should be subtracted that is 6 should be added to p(x)=4x4−2x3−6x2+x−5 so that the resulting polynomial is exactly divisible by q(x)=2x2+x–1.
Lets divide p(x)=4x4−2x3−6x2+x−5 by q(x)=2x2+x–1 as shown below:
Hence −6 should be subtracted that is 6 should be added to p(x)=4x4−2x3−6x2+x−5 so that the resulting polynomial is exactly divisible by q(x)=2x2+x–1.
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