___ $P a$ is the pressure at a depth of $9 m$ below the surface of the water tank. The density of water is $1000 k g / m^{3}$ .

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Solution

The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by $d g h$ .
The given values are: $d = 1000 k g / m^{3}$ , h = 9 m and $g = 10 m / s^{2}$
Thus, $p r e s s u r e = d g h$
$= 1000 \times 9 \times 10 = 90000 P a$

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