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नीचे दिए गए प्रश्न के लिए अनुच्छेद

The current through an inductor is given as i = (2 + 4t) A, where t is time in second. The magnitude of induced emf in the inductor is 2 V. Answer the following question.

एक प्रेरक से प्रवाहित धारा को i = (2 + 4t)A द्वारा व्यक्त किया जाता है, जहाँ t सेकण्ड में समय है। प्रेरक में प्रेरित वि.वा.ब. का परिमाण 2 V है। निम्नलिखित प्रश्न का उत्तर दीजिए।

Q. Total flux linked with the inductor at t = 4 s is

प्रश्न - t = 4 s पर प्रेरक से सम्बद्ध कुल फ्लक्स है

A
5 Wb
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B
9 Wb
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C
12 Wb
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D
15 Wb
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Solution

The correct option is B 9 Wb
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