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नीचे दिए गए प्रश्न के लिए अनुच्छेद

The current through an inductor is given as i = (2 + 4t) A, where t is time in second. The magnitude of induced emf in the inductor is 2 V. Answer the following questions.

एक प्रेरक से प्रवाहित धारा को i = (2 + 4t)A द्वारा व्यक्त किया जाता है, जहाँ t सेकण्ड में समय है। प्रेरक में प्रेरित वि.वा.ब. का परिमाण 2 V है। निम्नलिखित प्रश्न का उत्तर दीजिए।

Q. The self inductance of the inductor is

प्रश्न - प्रेरक का स्व-प्रेरकत्व है

A
0.2 H
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B
0.8 H
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C
0.5 H
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D
1 H
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Solution

The correct option is C 0.5 H
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