Question

Parul and Vijay throw 3 dice in a single throw. It is known that Parul throws a total of 16. Find Vijay’s probability of getting a higher value.

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

The maximum total possible = 18

There are two options for Vijay

1) A+B+C=17 Possibilities = 6,6,5

Number of combinations = $\frac{3!}{2!}$ =3

2) A+B+C=18Possibilities = 6,6,6

Number of combinations = 1

Required Probability= $\frac{4}{216}$ = $\frac{1}{52}$.

Option (c)