Passage-1 If n is the positive integer and if (1+4x+4x2)n=2n∑r=0arxr, where ar are real numbers. On the basis of above information answer the following questions. Sum of the coefficients is
A
4n
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B
1
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C
9n
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D
9
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Solution
The correct option is B9n (1+4x+2x2)n (1+2x)2n ...(i) =∑2n0arxr By substituting x=1 in equation (i), we get the sum of the coefficients of the binomial expansion of (1+2x)2n Hence answer is (1+2)2n =32n =9n