Question

Passing through the point (- 4, 3) with slope $\frac{1}{2}$

Answer 1

Here $x_0$ = - 4, $y_0$ = 3 and $m=\frac{1}{2}$

Putting these values in $y-y_0=m(x-x_0)$, we have

$\therefore y-3=\frac{1}{2}[x-(-4\left)\right]\Rightarrow 2y-6=x+4$

$\Rightarrow x-2y+10=0$