Question

Peeyush has prepared a solution which contains 30 g of sugar dissolved in 300 g of water. What will be the concentration of the solution in terms of mass by mass percentage prepared by him?

Answer 1

Given,
Mass of solute = 30 g
Mass of solvent = 300 g
So, Mass of solution = Mass of solute + Mass of solvent
= 30 + 300 = 330 g

Mass by mass percentage of a solution $=\frac{\text{mass of solute}}{\text{mass of solution}}\times 100$


On putting values in formula, we get
= (30/330)*100
= 9.09 %

Hence, Peeyush has prepared a solution of concentration 9.09% by mass.