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Algebra of Derivatives

Period of |...

Question

Period of $| sin x | + | cos x |$ is

\frac{π}{2}

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π

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\frac{3 π}{2}

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2 π

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Solution

The correct option is B $\frac{π}{2}$
$f (x) = | sin x |$
Period of $| sin x | = π$
$g (x) = | cos x |$
Period of $| cos x | = π$
So, period of $| sin x | + | cos x |$ $= \frac{1}{2} (L . C . M o f π, π) = \frac{π}{2}$
Hence, option 'A' is correct.

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