Permanent hardness is due to SO2−4 and Cl− of Ca2+ and Mg2+ and is removed by the addition of Na2CO3. CaSO4+Na2CO3⟶CaCO3+Na2SO4 CaCl2+Na2CO3⟶CaCO3+2NaCl If hardness is 100 ppm CaCO3, amount of Na2CO3 required to soften 10 L of hard water is :
A
2.12 g
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B
0.106 g.
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C
10.6 g
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D
1.06 g
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Solution
The correct option is B1.06 g Na2CO3106g=CaCO3100g Hardnessin106gH2O=100gCaCO3. ∴Hardnessin10L(104mL=104g)H2O=1gCaCO3. 100gCaCO3required=106gNa2CO3. ∴1gCaCO3required=1.06gNa2CO3.