Ph- C - N - Partial HydrolysisH3O- A - Br 2- KOH B Product B is-A- Ph - CH 2- NH 2B- Ph - OHC - P h - N H 2D- Ph - CH 3

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Reduction of Amides,Oximes and Azides with LAH

Ph- C ≡ N → P...

Question

$Ph - C \equiv N H_{3} O^{+} - --------- \to Partial Hydrolysis (A) {Br}_{2} + KOH - ---- \to (B)$
Product (B) is:

P h - C H_{2} - N H_{2}

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P h - O H

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P h - N H_{2}

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P h - C H_{3}

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Solution

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Similar questions

Ph - C \equiv N H_{3} O^{+} - --------- \to Partial Hydrolysis (A) {Br}_{2} + KOH - ---- \to (B)

Aniline C H C l_{3}, K O H - ------- \to Δ X L i A l H_{4} - --- \to Y

(Y)

Aniline N a N O_{2} - --- \to H C l A C u C N - --- \to B H_{2} - \to N i C H N O_{2} - --- \to D

C - C l

P h - C l | C H - {C H}_{3}

P h - {C H}_{2} - {C H}_{2} - C l

C H_{3} - O | | C - H (i); C H_{3} - O | | C - C H_{3} (i i); E t - O | | C - H (i i i)

C H_{3} - C H_{2} - C H_{2} - O | | C - H (i v); P h - O | | C - C H_{3} (v); P h - O | | C - P h (v i)

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