Ph-CH-CHCHO-CH3CH - CHCHO baseEtOH- - A87

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Cross Aldol Condensation

Ph-CH=CHCHO+C...

Question

$P h - C H = C H C H O + C H_{3} C H = C H C H O b a s e ⟶ E t O H, Δ (A)$ 87%;
Product(A) of this reaction is:

P h - (C H = C H)_{2} - C H O

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P h - (C H = C H)_{3} C H O

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P h - (C H = C H)_{4} C H O

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P h - C H = C H - C H = C H - C H_{3}

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Solution

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Similar questions

P h - C H = C H - C H_{2} B r H O H - -- \to [X]

[X]

(X)

(X) \Rightarrow P h - C H = C H - C | H C H_{3} - C H = C H - P h

C H_{3} C H O + H_{2} N O H - \to C H_{3} C H = N - O H

P h - C H = C H - O | | C - C H_{3} \to P h - C H = C H - C O_{2} H

P h - O | | S - C H = C H - C H_{2} - C H = C = C = C H - C H = C H - C H_{3}

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