Ph - O - CH 2- P h on treament with HI produces-A- P h - CH 2- IB- Ph - CH 2 OHC- P h - I

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Reduction of Amides,Oximes and Azides with LAH

Ph - O - CH 2...

Question

$P h - O - C H_{2} - P h$ on treament with $H I$ produces:

P h - C H_{2} - I

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P h - C H_{2} O H

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P h - I

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Solution

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Product (A) is :

Ph - C \equiv N H_{3} O^{+} - --------- \to Partial Hydrolysis (A) {Br}_{2} + KOH - ---- \to (B)

P h - O - C H_{2} - P h + H I \to

Aniline N a N O_{2} - --- \to H C l A C u C N - --- \to B H_{2} - \to N i C H N O_{2} - --- \to D

	Column I		Column II
A	$C H_{3} - C H B r - C D_{3}$ /on treatement with alc.KOH gives $C H_{2} = C H - C D_{3}$ as a major product	P	E1 reaction
B	$P h - C H B r - C H_{3}$ reacts faster than $P h - C H B r - C D_{3}$	Q	E2 reaction
C	$P h - C H_{2} - C H_{2} - F$ on treatement with $C_{2} H_{5} O D / C_{2} H_{5} O^{-}$ gives $P h - C D = C H_{2}$ as the major product	R	E1cB reaction
D	$P h - C H_{2} - C H_{2} - B r$ and $P h - C D_{2} - C H_{2} - B r$ react with same rate	S	First order reaction

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