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Henderson Hassleback Equation

pH of 0.5 M B...

Question

pH of 0.5 M $B a (C N)_{2}$ solution $(p K_{b} o f C N^{-} = 9.30)$ is :

8.35

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3.35

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9.35

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9.50

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Solution

The correct option is C
9.35

$[C N^{-}] = 2 \times 0.5 = 1.0 M p H = \frac{1}{2} (p K_{w} + p K_{a} + l o g [C N^{-}]) = \frac{1}{2} [14 + (14 - p K_{b}) + l o g 1] = \frac{1}{2} [28 - 9.30] = 9.35$

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