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pH of 10 -x...

Question

pH of $10^{- x} M$ $H C l$ is $6.9586$ .The value of $x$ will be:

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Solution

Formula for $p H$ is $p H = - l o g [H^{+}]$
$p H = 6.9586$
$\Rightarrow - l o g [H^{+}] = 6.958$
$[H^{+}] = 10^{- 6.958} = 10^{0.042} \times 10^{- 7} = 1 \times 10^{- 7}$
$[H^{+}] = 1 \times 10^{- 7}$
$x = 7$

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