You visited us 77 times! Enjoying our articles? Unlock Full Access!

pH of 10 -x...

Question

pH of $10^{- x} M$ $H C l$ is $6.9586$ .The value of $x$ will be:

Open in App

Solution

Formula for $p H$ is $p H = - l o g [H^{+}]$
$p H = 6.9586$
$\Rightarrow - l o g [H^{+}] = 6.958$
$[H^{+}] = 10^{- 6.958} = 10^{0.042} \times 10^{- 7} = 1 \times 10^{- 7}$
$[H^{+}] = 1 \times 10^{- 7}$
$x = 7$

Suggest Corrections

Similar questions

C a F_{2}

p H = 3.0

3.86 \times 10^{- x} M

x

K_{a}

H F = 6.3 \times 10^{- 4}

K_{s p}

C a F_{2} = 3.45 \times 10^{- 11}

10^{- 7}

H C l

1 m l

0.1

N H C l

1

p H

4

p H

5800

˚ A = 5.8 \times 10^{- x} m

x

20

x M

H C l

10

0.1 M

N a H C O_{3}

5

0.2 M

N a_{2} C O_{3}

x

Join BYJU'S Learning Program