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Byju's Answer
Standard IX
Chemistry
pH of a Solution
pH of a 0.0...
Question
p
H
of a
0.01
M
solution (
K
a
=
6.6
×
10
−
4
) is:
A
7.6
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B
8
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C
2.6
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D
5
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Solution
The correct option is
D
2.6
α
=
√
K
a
C
=
√
6.6
×
10
−
4
0.01
=
√
6.6
×
10
−
2
=
0.257
[
H
+
]
=
C
α
=
0.01
×
0.257
=
2.57
×
10
−
3
p
H
=
3
−
log
2.5
=
2.60
Suggest Corrections
0
Similar questions
Q.
The
[
H
+
]
of a resulting solution that is
0.01
M
acetic acid
(
K
a
=
1.8
×
10
−
5
)
and
0.01
M
in benzoic acid
(
K
a
=
6.3
×
10
−
5
)
:
Q.
The
p
H
of
0.01
M
solution of sodium salt of a substituted benzoic acid at
25
o
C
is:
(
K
a
=
1.0
×
10
−
4
at
25
o
C
)
Q.
What is the percent ionization
(
α
)
of a
0.01
M
H
A
solution?
(Given that
K
a
=
10
−
4
)
Q.
Calculate the degree of hydrolysis of
0.01
M
sodium acetate solution.
K
a
=
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×
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−
5
.
Q.
0.1
mole arsenic acid
(
H
3
A
s
O
4
)
is dissolved in a 1L buffer solution of
p
H
=
8
. Which of the following options is/are correct? For arsenic acid:
K
a
1
=
2.5
×
10
−
4
,
K
a
2
=
5
×
10
−
8
,
K
a
3
=
2
×
10
−
13
.
(‘<<’ sign denotes that the higher concentration is 100 times greater than the lower one or more)
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