Question

pH of a dilute solution HCL of is 6.95.
Calculate molarity of HCL solution.

Answer 1

molarity of the $HCl$ solution is its $H^{+}$ ion concentration in the solution

$pH$ is given by

$pH=-lo{g}_{10}\left[H^{+}\right]$

$log\left[H^{+}\right]=-pH$

= $-6.95$

= $-6-0.95-1+1$

= $-7+0.05$

= $\overline{7}.05$

$\left[H^{+}\right]=antilog\overline{7}.05$

= $1.12\times {10}^{-7}M$

Therefore, molarity of $HCl$ is $1.12\times {10}^{-7}M$