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Question

pH of a saturated solution of Ba(OH)2 is 12. The value of solubility product (Ksp) of Ba(OH)2 is :

A
3.3×107
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B
5.0×107
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C
4.0×106
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D
5.0×106
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Solution

The correct option is B 5.0×107
Ba(OH)2Ba2+s+2OH2s
[OH]=102
2s=102
s=1022
Ksp=4s3
=4×(1022)3
=5×107=5×107

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