Question

$pH$ of a solution is $3$, by adding water, the $pH$ of the same solution becomes $6$. How many times dilution increased?

• A. $100$ times
• B. $10$ times
• C. $1000$ times
• D. None of these

Answer 1

The correct option is C $1000$ times

As we know that
$pH\propto dilution$
Originally $pH$ of the solution is $3$
$\therefore \left[H^{+}\right]={10}^{-3}$
After dilution $pH$ became $6$
$\left[H^{+}\right]={10}^{-6}$
Dilution increased
$=\frac{Original{H}^{+}concentration}{Conc.H^{+}afterdilution}=\frac{{10}^{-3}}{{10}^{-6}}={10}^3$
Hence, dilution became $1000$ times.