Question

$pH$ of a solution of a strong acid is 5.0. What will be the pH of the solution obtained by diluting the given solution 100 times?

Answer 1

$pH=5$

$-\log \left[H^{+}\right]=5$

$\left[H^{+}\right]=$antilog $(-5)$

$\left[H^{+}\right]={10}^{-5}$

now concentration diluted by $100$ times

$\left[H^{+}\right]={10}^{-7}$

now, $pH=7$