Question

$PhCH=C{H}_2\underset{2.H_2{O}_2/OH}{\stackrel{1.B_2{H}_6/THF}{\to }}X\stackrel{PCC\left(C{H}_{2}C{l}_2\right)}{\to }Y\stackrel{OH-/heat}{\to }Z$.

Identify $X,Y,$ and $Z$ in the above reaction.

Answer 1

First reaction is Hybridization- oxidation which gives anti- Markonikov $-OH$ addition.

$Ph-CH=C{H}_2\stackrel{1.B_2{H}_6/THF}{\underset{2.H_2{O}_2/OH}{⟶}}\underset{X}{\underset{}{Ph-C{H}_2-C{H}_{2}OH}}$

Second reaction gives oxidation of alcohol to aldehyde as shown in IMAGE $01$.

Third reaction is Aldol condensation as shown in IMAGE $02$