$P h C H O N a O H - --- \to P h C H_{2} O H + P h C O_{2} N a$
In the cannizaro reaction given above, the slowest step is :

the attack of

O H^{-}

at the carbonyl group

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the transfer of hydride to the carbonyl group

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the abstraction of proton form the carboxylic group

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deprotonation of

P h C H_{2} O H

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Solution

The correct option is B the transfer of hydride to the carbonyl group

The mechanism of Cannizzaro reaction involves 3 steps.

The first step is the addition of hydroxide ion to carbonyl group. It is reversible reaction.

The second step is the transfer of hydride ion from hydroxy alkoxide to another aldehyde molecule. It is slowest step.

Third step is the exchange of proton between the acid and alkoxide ion.

Option B is correct.

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Similar questions

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h C H O O H^{-} - -- \to p h C H_{2} + p h C O_{2}^{-} .

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

2 P h C H O : O H \to P h C H_{2} O H + P h C O O^{-}

C C l_{3} C O O^{-}

C C l_{3} C H_{2} O H

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