Phenyl cyanide on reduction with $N a / C_{2} H_{5} O H$ yields:

C_{6} H_{5} N H_{2}

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C_{6} H_{5} N H C H_{3}

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C_{6} H_{5} C H_{2} N H_{2}

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Solution

The correct option is D $C_{6} H_{5} C H_{2} N H_{2}$
Phenyl cyanide (benzonitrile) on reduction with sodium ethanol produces benzyl amine.
With the help of this reagent, $- C \equiv N$ group is reduced to $C H_{2} - N H_{2}$ group.
$P h - C \equiv N Na(Hg)-ethanol - -------- \to P h - C H_{2} - N H_{2}$
Hence, the correct answer is option (a).

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