1
Question
Phosphine (PH3) decomposes to produce P4(g) and H2(g). What would be the change in volume when 100 mL of PH3(g) is completely decomposed?
Phosphine (PH3) decomposes to produce P4(g) and H2(g). What would be the change in volume when 100 mL of PH3(g) is completely decomposed?
Open in App
Solution
The correct option is C 75 mL
The decomposition of PH3 takes place as,
4PH3→P4+6H2
From the balanced equation,
4 mol of PH3 produces 6 mol of H2
and 1 mol of P4
So in terms of volume,
4 ml of PH3 produces 6 ml H2 and 1 ml P4
So, when 100 ml of PH3 decomposes, volume of the products will be, 74×100=175 ml
So the required change in volume is =175−100 ml=75 ml
The decomposition of PH3 takes place as,
4PH3→P4+6H2
From the balanced equation,
4 mol of PH3 produces 6 mol of H2
and 1 mol of P4
So in terms of volume,
4 ml of PH3 produces 6 ml H2 and 1 ml P4
So, when 100 ml of PH3 decomposes, volume of the products will be, 74×100=175 ml
So the required change in volume is =175−100 ml=75 ml
Suggest Corrections
26
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
